screenX and screenY property tutorial in JavaScript
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0, shrink-to-fit=no">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>screenX screenY property JavaScript</title>
<link rel="stylesheet" href="css/screenX_screenY_property_JavaScript.css">
</head>
<body>
<h2>JavaScript screenX & screenY</h2>
<div id="box"></div>
<script>
// document.addEventListener("mousemove",function(e){
// console.clear();
// var x = e.screenX;
// var y = e.screenY;
// console.log("screenX : " + x);
// console.log("screenY : " + y);
// });
//For box, when we click on box then only x and y value updated in console
// document.querySelector("#box").addEventListener("mousemove", function (e) {
// console.clear();
// var x = e.screenX;
// var y = e.screenY;
// console.log("screenX : " + x);
// console.log("screenY : " + y);
// });
//Below Code is for mouse "click" Event
document.querySelector("#box").addEventListener("click", function (e) {
console.clear();
var x = e.screenX;
var y = e.screenY;
var x2 = e.clientX;
var y2 = e.clientY;
console.log("screenX : " + x);
console.log("clientX : " + x2);
console.log("screenY : " + y);
console.log("clientY : " + y2);
});
</script>
</body>
</html>
Below File is css/screenX_screenY_property_JavaScript.css File
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